x^4-10x^2+48=0

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Solution for x^4-10x^2+48=0 equation:


Simplifying
x4 + -10x2 + 48 = 0

Reorder the terms:
48 + -10x2 + x4 = 0

Solving
48 + -10x2 + x4 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-48' to each side of the equation.
48 + -10x2 + -48 + x4 = 0 + -48

Reorder the terms:
48 + -48 + -10x2 + x4 = 0 + -48

Combine like terms: 48 + -48 = 0
0 + -10x2 + x4 = 0 + -48
-10x2 + x4 = 0 + -48

Combine like terms: 0 + -48 = -48
-10x2 + x4 = -48

The x term is -10x2.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x2 + 25 + x4 = -48 + 25

Reorder the terms:
25 + -10x2 + x4 = -48 + 25

Combine like terms: -48 + 25 = -23
25 + -10x2 + x4 = -23

Factor a perfect square on the left side:
(x2 + -5)(x2 + -5) = -23

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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